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398 days ago by akrobat

reset() forget() var("r,ksi,a3,A") aa=-r^2*(ksi+a3)+I*sqrt(A)*r bb=-(ksi+a3)*(r-I*sqrt(A)/(2*(ksi+a3)))^2 + (ksi+a3)*(I*sqrt(A)/(2*(ksi+a3)))^2 
       
print(bb) 
        
-1/4*(2*r - I*sqrt(A)/(a3 + ksi))^2*(a3 + ksi) - 1/4*A/(a3 + ksi)
-1/4*(2*r - I*sqrt(A)/(a3 + ksi))^2*(a3 + ksi) - 1/4*A/(a3 + ksi)
show(-1/4*(2*r - I*sqrt(A)/(a3 + ksi))^2*(a3 + ksi) - 1/4*A/(a3 + ksi)) 
        
\newcommand{\Bold}[1]{\mathbf{#1}}-\frac{1}{4} \, {\left(2 \, r - \frac{i \, \sqrt{A}}{a_{3} + \mbox{ksi}}\right)}^{2} {\left(a_{3} + \mbox{ksi}\right)} - \frac{A}{4 \, {\left(a_{3} + \mbox{ksi}\right)}}
\newcommand{\Bold}[1]{\mathbf{#1}}-\frac{1}{4} \, {\left(2 \, r - \frac{i \, \sqrt{A}}{a_{3} + \mbox{ksi}}\right)}^{2} {\left(a_{3} + \mbox{ksi}\right)} - \frac{A}{4 \, {\left(a_{3} + \mbox{ksi}\right)}}
show(bb) 
        
\newcommand{\Bold}[1]{\mathbf{#1}}-\frac{1}{4} \, {\left(2 \, r - \frac{i \, \sqrt{A}}{a_{3} + \mbox{ksi}}\right)}^{2} {\left(a_{3} + \mbox{ksi}\right)} - \frac{\frac{1}{4} \, A}{4 \, {\left(a_{3} + \mbox{ksi}\right)}}
\newcommand{\Bold}[1]{\mathbf{#1}}-\frac{1}{4} \, {\left(2 \, r - \frac{i \, \sqrt{A}}{a_{3} + \mbox{ksi}}\right)}^{2} {\left(a_{3} + \mbox{ksi}\right)} - \frac{\frac{1}{4} \, A}{4 \, {\left(a_{3} + \mbox{ksi}\right)}}