kfg math 010 answers

Math 010 4148 June 15, 2011 #Name ____________kfg_____________________________ #Date/Time Submitted _12:35am__6/17/2011_______ section #5.6 1a) z+0.8==2.5 z+0.8-0.8==2.5-0.8 z==1.7 section#5.6 1b) 0.27x=-0.81 0.27x/0.27=-0.81/0.27 x=-3 section#5.7 1a) mean 71+47+71+99+47 =335/5 =67 find the mean 85+78+67 ==230/3 ==76.666 find media 1,2,3,4,5,6 ==3+4 =7/2=3.5 mode 1,2,2,3,5 mode 2 

Traceback (click to the left of this block for traceback)
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SyntaxError: invalid syntax

Traceback (most recent call last):    z+0.8-0.8==2.5-0.8
  File "", line 1, in <module>
    
  File "/tmp/tmpzf9UGB/___code___.py", line 3
    Math _sage_const_010   _sage_const_4148    June _sage_const_15 , _sage_const_2011 
                       ^
SyntaxError: invalid syntax

#Make a copy and rename your file. Please do not make any changes to this shared file #Extra credit work equivalent to one quiz # Answers to worksheets 5.6 and 5.7 # Use the format shown here: #Section# Item# Question # Due date: Saturday June 18. (One quiz - minimum) # The earlier, the better (more extra credits!) 

#5.6 1a) Solve z+0.8 = 2.5 

#5.6 1b) Solve 0.27x = -0.81 

#5.7 1a) Find the mean of 71,47,71,99,47 71 + 47 + 71 + 99 +47 #correct this entry...is it enough to just add the numbers 

335

335

#Check your above answer using the mean() command mean([85.,78.,67.]) #using decimals, will give us decimal answer 

76.6666666666667

76.6666666666667

mean([85 ,78 ,67]) #using whole numbers will give us (usually a fraction in lowest terms) 

230/3

230/3

#Just use mode() command in SAGE to find mode mode([1,2,2,3,5]) #Use square brackets to define list of numbers 

[2]

[2]

#Just use median() command in SAGE to find median median([1.,2.,3.,4.,5.,5.]) # "decimalize" to get a decimal answer :) 

3.50000000000000

3.50000000000000